Using simpleTimer setTimer function for multiple time

Solved
1

Hello, I try to avoid delay because it cause Blynk to not run correctly, I Can’t figure out how to use simpleTimer to turn on buzzer for multiple different time.
for Example :
I have two buttons connected to D3 and D4 and buzzer to D2. and if D3 is pressed I want to beep buzzer for 3 time and if D4 is pressed I want to beep buzzer for 4 times and so on.
I tried use setTimer function with enable and disable TimerID but I can call setTimer ID only once time after pressed D3, or D4. need help!

2

It might be easier if we saw the script you are currently working with… but basicly it should be a simple matter of adjusting timeouts before turning off the buzzer… now pulsing the buzzer via timers then shutting it off is a bit more effort, but still doable.

I use this (possibly crude, but effective) code to latch a relay then flash an LED five (5) times, with 1 second pulses.

Read through it to see how it is done, then adapt it for your needs.

//===== LATCH (Relay) & LED PULSE - BLYNK Functions =====
BLYNK_WRITE(V40)  // Virtual button on V40 to activate Relay_LED pulses
{
  RLY_LED = param.asInt();
  if (RLY_LED == 1 && Flag == 0){
    Flag = 1;  // Keeps from allowing button press more then once while relay activated
    digitalWrite(30, HIGH); // Activate Relay
    timer.setTimeout(2000L, Relay2OFF);  // Deactivare Relay after 2 seconds
    timer.setTimer(2000L, LedON, 5);  // Pulse LED routine (LedON/LedOFF) 5 times
  }  // END if
}  // END Blynk Function

void Relay2OFF()
{
  digitalWrite(30, LOW);
  Flag = 0;  // reset flag after relay disables
}  // END Relay2OFF Function

void LedON()
{
  digitalWrite(31, HIGH);  // Turn on LED
  timer.setTimeout(1000L, LedOFF);  // Run OFFLED routine once in 1 second
}  // END LedON Function

void LedOFF()
{
  digitalWrite(31, LOW);  // Turn off LED
}  // END LedOFF Function
3

thanks, you always helpful.