How do I create it, I’m running on windows 10 and I couldn’t find any sources on how to do it on Windows 10.
The application OpenSSL will only run on computer from Win XP x64 to Win 7 x64 bit OS running machines.
I have successfully started and connected my phone and hardware to the server, how do I change the domain address and make the website secure. I entered what my domian name needs to be on the line as server.host=smome.com , I changed the line on contact.email as contact.emal=MyEmailId , I enabled allow less secure apps setting and i started the server and the server doesn’t give the output as
Have you opened port 80 on your router/firewall? And redirected to your server pc? I noticed that lets encrypt stopped working when I closed it so I reopened it.
that port on my computer is open and my pc’s firewall is permanently diabled
#hardware mqtt port
hardware.mqtt.port=8440
#hardware ssl port
hardware.ssl.port=8441
#hardware plain tcp/ip port
hardware.default.port=8442
#http, plain web sockets and plain hardware port
http.port=80
#secured https, web sockets and app port
https.port=9443
this is a pat ofmy server.properties code, did I make any mistakes ? please let me know.
It’s not a DNS or FTP server those are other types. I do not know what category blynk server falls under.
It runs on java and uses a custom TCP/IP protocol.
Static IP you must(preferably) set in your router, As I do not know how it looks on your specific router I can’t help you right now. You need the MAC adress of your server PC aswell for the “identification”. Poke around your routers DCHP settings. edit:
Static IP is a user choice, you can use the current one by opening command prompt and writing ipconfig /all
look for physical adress, that is your MAC
look for IPv4 address, that is your server pcs current local address
Your settings are wrong. Please try these and avoid misstyping, its port 443 not 433.
It is something localy on your network or PC that is blocking port 443. There is no need to change it as it will likely move the issue to another port.