Email and Push Notifications on Particle Photon

Need Help With My Project
1

I’m attempting to use the Push Notification example sketch (on Blynk’s documentation website) with my Photon but I’m running into issues with this command:

attachInterrupt(digitalPinToInterrupt(2), notifyOnButtonPress, CHANGE);

The Photon doesn’t recognize “digitalPinToInterrupt(2)” syntax.

I’ve tried the following which will all complie:

attachInterrupt(D2, notifyOnButtonPress, CHANGE);
attachInterrupt(2, notifyOnButtonPress, CHANGE);
attachInterrupt(V2, notifyOnButtonPress, CHANGE);

but still am unable to Push a Notification when I press the button…My Photon also freezes up if I press the button too many times repeatedly but I believe this is due to the 1 Push msg per minute limit.

Any suggestions would be much appreciated!
Thanks,

-Jp-

2

In general, you should ask this kind of question on Particle forums.
Anyway, I hope maybe someone from the community can answer it.

Cheers.

3

Ok so I’ve had a little more time to play with this and here is my discovery:

I can run this code with out the particle Photon freezing up:

#include "blynk/blynk.h"
#define BLYNK_PRINT Serial

 volatile int state = LOW;

void setup()
{
 Serial.begin(9600);
 Blynk.begin(auth);
 attachInterrupt(D7, notifyOnButtonPress, CHANGE);
}

void notifyOnButtonPress()
{
state = !state;
}

void loop()
{
 Blynk.run();
}

But the below code will freeze up the Photon and it will no longer respond to commands (and stays solid cyan after the button press, instead of “breathing cyan”) :

#include "blynk/blynk.h"
#define BLYNK_PRINT Serial

void setup()
{
 Serial.begin(9600);
 Blynk.begin(auth);
 attachInterrupt(D7, notifyOnButtonPress, CHANGE);
}

void notifyOnButtonPress()
{
Blynk.notify("Yaaay... button is pressed!");
}

void loop()
{
 Blynk.run();
}

This leads me to think that the Blynk.notify() command doesn’t play well with the attachInterupt() command??? What do you think the issue could be?

4

Yes, it may be the problem.
Not all functions may behave well in interrupt context.
You can make a new variable and use it as a flag to run .notify() inside of loop().

Hope that helps.